Weight Lifted with Bodyweight Dips?

[quote]Sabastian525 wrote:
If you want to get technical, the amount of force generated is directly proportional to the acceleration applied to the mass. So it’s not such a straight-line equation after all, it’s more of a second order exponential, Newtonian physics problem.

Force = mass * acceleration

So you’re actually lifting “more” when you’re going up, “less” when you’re going down, and only holding exactly your bodyweight when you’re in the locked position.

However, none of this matters at all.

-Sab[/quote]

You’re supporting all of your bodyweight except your hands, but you’re only lifting from the elbows up. Don’t forget that since the upper arms travel in an arc, there’s actually an integral you have to do there since the torque required changes as it goes towards vertical. The distal portion of your upper arm doesn’t move near as much as the proximal portion.

Based on the responses here, I’d say that if you HAD to have a number, you should figure 90% of your bodyweight for a bodyweight dip, leave it at that, and go do some.

Don’t forget to do the integral though, as that’s important. o.O

feet of floor,hands on handles, no support let me think…unless your doing weighted then 100%+ …hmmmmm…

The reason you’re not getting a “good” answer is because you did not ask a “good” question.

If I weigh 200 lbs and squat 400 lbs, it doesn’t matter what percentage of my bodyweight is being lifted… I’m still only squatting 400 lbs.

If you really care that much, hang upside-down from your ankles and do BB press, then you will know exactly how much you are doing.

[quote]HolyMacaroni wrote:
I put my hand upon your hip…

when you dip, i dip, we dip[/quote]

You put yours, and I put mine, and we can dip down low and roll and grind!

[quote]nschneid wrote:
Sabastian525 wrote:
If you want to get technical, the amount of force generated is directly proportional to the acceleration applied to the mass. So it’s not such a straight-line equation after all, it’s more of a second order exponential, Newtonian physics problem.

Force = mass * acceleration

So you’re actually lifting “more” when you’re going up, “less” when you’re going down, and only holding exactly your bodyweight when you’re in the locked position.

However, none of this matters at all.

-Sab

You’re supporting all of your bodyweight except your hands, but you’re only lifting from the elbows up. Don’t forget that since the upper arms travel in an arc, there’s actually an integral you have to do there since the torque required changes as it goes towards vertical. The distal portion of your upper arm doesn’t move near as much as the proximal portion.

Based on the responses here, I’d say that if you HAD to have a number, you should figure 90% of your bodyweight for a bodyweight dip, leave it at that, and go do some.

Don’t forget to do the integral though, as that’s important. o.O
[/quote]

Are you kidding me? You’re lifting all your bodyweight except your hands?

Regardless of bar width, hand placement, forward lean, or whether or not you can see venus in the fucking twilight sky, you are moving ALL your bodyweight during a dip.

[quote]Itchy wrote:
nschneid wrote:
Sabastian525 wrote:
If you want to get technical, the amount of force generated is directly proportional to the acceleration applied to the mass. So it’s not such a straight-line equation after all, it’s more of a second order exponential, Newtonian physics problem.

Force = mass * acceleration

So you’re actually lifting “more” when you’re going up, “less” when you’re going down, and only holding exactly your bodyweight when you’re in the locked position.

However, none of this matters at all.

-Sab

You’re supporting all of your bodyweight except your hands, but you’re only lifting from the elbows up. Don’t forget that since the upper arms travel in an arc, there’s actually an integral you have to do there since the torque required changes as it goes towards vertical. The distal portion of your upper arm doesn’t move near as much as the proximal portion.

Based on the responses here, I’d say that if you HAD to have a number, you should figure 90% of your bodyweight for a bodyweight dip, leave it at that, and go do some.

Don’t forget to do the integral though, as that’s important. o.O

Are you kidding me? You’re lifting all your bodyweight except your hands?

Regardless of bar width, hand placement, forward lean, or whether or not you can see venus in the fucking twilight sky, you are moving ALL your bodyweight during a dip.

[/quote]

No, he’s right. Your hands are supported by the reactive force from the handles, as is everything else below the elbow.

[quote]Itchy wrote:
nschneid wrote:
Sabastian525 wrote:
If you want to get technical, the amount of force generated is directly proportional to the acceleration applied to the mass. So it’s not such a straight-line equation after all, it’s more of a second order exponential, Newtonian physics problem.

Force = mass * acceleration

So you’re actually lifting “more” when you’re going up, “less” when you’re going down, and only holding exactly your bodyweight when you’re in the locked position.

However, none of this matters at all.

-Sab

You’re supporting all of your bodyweight except your hands, but you’re only lifting from the elbows up. Don’t forget that since the upper arms travel in an arc, there’s actually an integral you have to do there since the torque required changes as it goes towards vertical. The distal portion of your upper arm doesn’t move near as much as the proximal portion.

Based on the responses here, I’d say that if you HAD to have a number, you should figure 90% of your bodyweight for a bodyweight dip, leave it at that, and go do some.

Don’t forget to do the integral though, as that’s important. o.O

Are you kidding me? You’re lifting all your bodyweight except your hands?

Regardless of bar width, hand placement, forward lean, or whether or not you can see venus in the fucking twilight sky, you are moving ALL your bodyweight during a dip.

[/quote]

edit: ninja beat me to it

[quote]trav123456 wrote:
Itchy wrote:
nschneid wrote:
Sabastian525 wrote:
If you want to get technical, the amount of force generated is directly proportional to the acceleration applied to the mass. So it’s not such a straight-line equation after all, it’s more of a second order exponential, Newtonian physics problem.

Force = mass * acceleration

So you’re actually lifting “more” when you’re going up, “less” when you’re going down, and only holding exactly your bodyweight when you’re in the locked position.

However, none of this matters at all.

-Sab

You’re supporting all of your bodyweight except your hands, but you’re only lifting from the elbows up. Don’t forget that since the upper arms travel in an arc, there’s actually an integral you have to do there since the torque required changes as it goes towards vertical. The distal portion of your upper arm doesn’t move near as much as the proximal portion.

Based on the responses here, I’d say that if you HAD to have a number, you should figure 90% of your bodyweight for a bodyweight dip, leave it at that, and go do some.

Don’t forget to do the integral though, as that’s important. o.O

Are you kidding me? You’re lifting all your bodyweight except your hands?

Regardless of bar width, hand placement, forward lean, or whether or not you can see venus in the fucking twilight sky, you are moving ALL your bodyweight during a dip.

edit: ninja beat me to it[/quote]
Well, I am a ninja :stuck_out_tongue:

[quote]ninjaboy wrote:
Itchy wrote:
nschneid wrote:
Sabastian525 wrote:
If you want to get technical, the amount of force generated is directly proportional to the acceleration applied to the mass. So it’s not such a straight-line equation after all, it’s more of a second order exponential, Newtonian physics problem.

Force = mass * acceleration

So you’re actually lifting “more” when you’re going up, “less” when you’re going down, and only holding exactly your bodyweight when you’re in the locked position.

However, none of this matters at all.

-Sab

You’re supporting all of your bodyweight except your hands, but you’re only lifting from the elbows up. Don’t forget that since the upper arms travel in an arc, there’s actually an integral you have to do there since the torque required changes as it goes towards vertical. The distal portion of your upper arm doesn’t move near as much as the proximal portion.

Based on the responses here, I’d say that if you HAD to have a number, you should figure 90% of your bodyweight for a bodyweight dip, leave it at that, and go do some.

Don’t forget to do the integral though, as that’s important. o.O

Are you kidding me? You’re lifting all your bodyweight except your hands?

Regardless of bar width, hand placement, forward lean, or whether or not you can see venus in the fucking twilight sky, you are moving ALL your bodyweight during a dip.

No, he’s right. Your hands are supported by the reactive force from the handles, as is everything else below the elbow.
[/quote]

Faulty logic and also irrelevant.

Do you guys weigh your arms and add that to your bench press numbers, too?

[quote]Itchy wrote:
ninjaboy wrote:
Itchy wrote:
nschneid wrote:
Sabastian525 wrote:
If you want to get technical, the amount of force generated is directly proportional to the acceleration applied to the mass. So it’s not such a straight-line equation after all, it’s more of a second order exponential, Newtonian physics problem.

Force = mass * acceleration

So you’re actually lifting “more” when you’re going up, “less” when you’re going down, and only holding exactly your bodyweight when you’re in the locked position.

However, none of this matters at all.

-Sab

You’re supporting all of your bodyweight except your hands, but you’re only lifting from the elbows up. Don’t forget that since the upper arms travel in an arc, there’s actually an integral you have to do there since the torque required changes as it goes towards vertical. The distal portion of your upper arm doesn’t move near as much as the proximal portion.

Based on the responses here, I’d say that if you HAD to have a number, you should figure 90% of your bodyweight for a bodyweight dip, leave it at that, and go do some.

Don’t forget to do the integral though, as that’s important. o.O

Are you kidding me? You’re lifting all your bodyweight except your hands?

Regardless of bar width, hand placement, forward lean, or whether or not you can see venus in the fucking twilight sky, you are moving ALL your bodyweight during a dip.

No, he’s right. Your hands are supported by the reactive force from the handles, as is everything else below the elbow.

Faulty logic and also irrelevant.

Do you guys weigh your arms and add that to your bench press numbers, too?
[/quote]

Um, no, it’s physics. And while I agree that the whole discussion is irrelevant, that in and of itself in irrelevant to the correctness of your statement. We aren’t talking about how a normal person would record the weight, we’re talking about the amount of weight actually moved during the exercise.

haha where’s the OP go anyways?
answer is cut off forearms and hands and weigh them and subtract them from your BW lol

[quote]Chris Colucci wrote:
IsolatedSingular wrote:
Anyone know what the percentage of your body weight you actually press during a dip? I’ve searched this site for the last 45 minutes to no avail.

Does it really matter if a “bodyweight dip” really only has you lifting “eleven-twelfths bodyweight”? If a “bodyweight” dip is too challenging, there are several ways to reduce the load or improve leverage (assistance machines, band assistance, partial reps, etc.)

But just for squirts and giggles, I spent all of 45 seconds Googling, and it looks like the average human arm is about 5-6% of your total bodyweight (that’s average, as in, not specifically weight-trained).

So if I’m 210 pounds, I’ll err on the side of a mild ego and say I’m sporting a pair of 13 pounds guns and when I do bodyweight dips (which, interesting side note, I never do), I’m actually “only” lifting about 184 pounds.

But really, when you think about it, your upper arm (from the elbow to the shoulder) is still actually moving, so you could probably make a case that you’re lifting that part as well, which throw off the above calculations and makes me think dear sweet mother of all things holy, why the hell are we trying to put this much effort into figuring this out?!?[/quote]

A lot of weird replies in here. Chris’s seems like the closest to answering the OP’s question, which is not really a dumb question. All your body except your arms moves the same amount vertically, assuming you’re not kipping and squirming. A part of your arm 1/3 of the way from your wrist to your shoulder moves only 1/3 as far, so it will seem to add only 1/3 of its weight. Depending on the distribution of weight along your arms, you can subtract the weight of your hands and some fraction of the weight of your arms. Unless your upper and lower arms look the same (some skinny girls, maybe), the fraction is a lot less than 1/2. Taking Chris’s number of 5-6% bodyweight per arm, two arms, less than one half, but toss out the hands, maybe an ok guess is:

Subtract 5% of your bodyweight.

Not a big deal, obviously, 10 lbs for a 200-lb man. Maybe subtract a little more if you have major arm development or strangler hands, a little less if you are fat. Or measure your arm mass distribution and do the integral.

For the record I was being a dork on purpose…

I always consider bodyweight dips to be 0. What matters is what you did last week compared to what you’re doing now. Change.

They’re just one exercise, unlike bench, that you can’t really compare person to person unless you start digging into completely irrelevant details because yeah, for a 300 lb guys, he’s obviously dipping a lot more than someone who weighs 150, but neither of them probably care what exactly that difference is.

it’s all good :wink:
dips ftw

[quote]Gillium-001 wrote:
Arg! Fiziks hurt meathead brain!
[/quote]

LOL for a long time.

Methinks you’re overthinking it. When you can move it for 16 reps add more weight.