Do the Math

[quote]Bujo wrote:
Another geometry puzzle.

You are in an empty room and you have a transparent glass of water. And I do mean empty. Its you, the glass and the water. That’s it. Nothing Else.

The glass is a right cylinder. It looks like it’s half full, but you’re not sure. How can you accurately figure out whether the glass is half full, more than half full, or less than half full? You have no rulers, no writing utensils, nor any etching tools.

[/quote]

Tilt it. If the line of the water lines up with the one side of the top and the opposing side of the bottom. It is half full/empty. If some spills out it is more than half full. If it doesn’t line up, it is less than half full. Because 1/2 of the volume would be 1/2 the volume regardless of the angle.

This is assuming the glass is large enough to disregard the meniscus.

A classic riddle that many up in arms over.

Suppose you’re on a game show, and you’re given the choice of three doors. Behind one door is a car, the others, goats. You pick a door, say #1, and the host, who knows what’s behind the doors, opens another door, say #3, which has a goat. He says to you: ‘Do you want to pick door #2?’ Is it to your advantage to switch your choice of doors?

[quote]Bujo wrote:
A classic riddle that many up in arms over.

Suppose you’re on a game show, and you’re given the choice of three doors. Behind one door is a car, the others, goats. You pick a door, say #1, and the host, who knows what’s behind the doors, opens another door, say #3, which has a goat. He says to you: ‘Do you want to pick door #2?’ Is it to your advantage to switch your choice of doors?[/quote]

Your odds are 2/3 if you switch because if you don’t you have a 1/3 chance of winning.

Of course, this problem introduces psychology of the host. Does he say it in a way to make you want to switch? Does he want to see you win or lose? Does he speak in a suggestive tone?

[quote]Chewie wrote:
Bujo wrote:
I want to have safe sex with three women, any of whom may be carrying an STD (I like the classy dames). However, I only have two condoms :frowning:

How do I fuck each one while ensuring that no STD is passed from one woman to another or to myself for that matter?

  1. Put two on at once. Have sex.
  2. Take the top one off. Have sex again.
  3. Flip the top one inside out and put it over the bottom one.

That’s gross.

[/quote]

Wrong. Have sex with them one at a time. Use condom #1 with girl #1, condom #2 with girl #2 and have anal sex with girl #3 without a condom. I thought everyone knows that hetero men can’t get STDs from anal sex with girls.

DB

[quote]Bujo wrote:
A classic riddle that many up in arms over.

Suppose you’re on a game show, and you’re given the choice of three doors. Behind one door is a car, the others, goats. You pick a door, say #1, and the host, who knows what’s behind the doors, opens another door, say #3, which has a goat. He says to you: ‘Do you want to pick door #2?’ Is it to your advantage to switch your choice of doors?[/quote]

Clearly, I would switch my pick to door #3. I already have two cars, but I don’t have a goat.

DB

Place 8 Queens on a chess board in a manner in which none can capture another.

[quote]Chewie wrote:
Bujo wrote:
A classic riddle that many up in arms over.

Suppose you’re on a game show, and you’re given the choice of three doors. Behind one door is a car, the others, goats. You pick a door, say #1, and the host, who knows what’s behind the doors, opens another door, say #3, which has a goat. He says to you: ‘Do you want to pick door #2?’ Is it to your advantage to switch your choice of doors?

Your odds are 2/3 if you switch because if you don’t you have a 1/3 chance of winning.

Of course, this problem introduces psychology of the host. Does he say it in a way to make you want to switch? Does he want to see you win or lose? Does he speak in a suggestive tone?

[/quote]

We either have similar hobbies or kill time on similar websites.

[quote]mazevedo wrote:
bushidobadboy wrote:
Here’s another mathmatical fallacy:

The population of the universe is effectively ZERO.

How so? Well the universe is infinite, yet the number of lifeforms in it is finite.

A finite number divided by infinity is equal to 0, therefore the population of the universe is ZERO.

Bushy

I don’t think it’s EQUAL to zero, I think it approaches zero as the infinite number approaches infinity. That’s called it’s limit.

And that right there was probably the first and last time I’ve ever used calculus outside the class.

[/quote]

I am glad I am reading this thread before my calc test tomorrow hahahahahhaa

[quote]Bujo wrote:
Chewie wrote:
Bujo wrote:
A classic riddle that many up in arms over.

Suppose you’re on a game show, and you’re given the choice of three doors. Behind one door is a car, the others, goats. You pick a door, say #1, and the host, who knows what’s behind the doors, opens another door, say #3, which has a goat. He says to you: ‘Do you want to pick door #2?’ Is it to your advantage to switch your choice of doors?

Your odds are 2/3 if you switch because if you don’t you have a 1/3 chance of winning.

Of course, this problem introduces psychology of the host. Does he say it in a way to make you want to switch? Does he want to see you win or lose? Does he speak in a suggestive tone?

We either have similar hobbies or kill time on similar websites.

[/quote]
It’s an engineer thing.

Did I get them right?

[quote]Bujo wrote:
Place 8 Queens on a chess board in a manner in which none can capture another.[/quote]

a5, b1, c6, d2, e7, f3, g8, h4

[quote]Chewie wrote:
Bujo wrote:
Place 8 Queens on a chess board in a manner in which none can capture another.

a5, b1, c6, d2, e7, f3, g8, h4[/quote]

That solution doesn’t work. (Unless I misunderstand your notation.)

a2, b4, c6, d8, e3, f1, g7, h5

Of course there are several other solutions.

[quote]Chewie wrote:
Bujo wrote:
Chewie wrote:
Bujo wrote:
A classic riddle that many up in arms over.

Suppose you’re on a game show, and you’re given the choice of three doors. Behind one door is a car, the others, goats. You pick a door, say #1, and the host, who knows what’s behind the doors, opens another door, say #3, which has a goat. He says to you: ‘Do you want to pick door #2?’ Is it to your advantage to switch your choice of doors?

Your odds are 2/3 if you switch because if you don’t you have a 1/3 chance of winning.

Of course, this problem introduces psychology of the host. Does he say it in a way to make you want to switch? Does he want to see you win or lose? Does he speak in a suggestive tone?

We either have similar hobbies or kill time on similar websites.

It’s an engineer thing.

Did I get them right?
[/quote]

Yeah, you got’em right. It probably is an engineer thing. I’m a mechanical engineer, and when not screwing off on T-Nation I’m screwing off playing with math or logic puzzles. Anything to keep from doing real work.

[quote]Chewie wrote:
Bujo wrote:
Place 8 Queens on a chess board in a manner in which none can capture another.

a5, b1, c6, d2, e7, f3, g8, h4 [/quote]

I didn’t see anything wrong with that solution.

Of course if you made all the queens the same color then it wouldn’t matter where on the board they were placed. :wink:

[quote]Bujo wrote:
a5, b1, c6, d2, e7, f3, g8, h4

I didn’t see anything wrong with that solution.

[/quote]

a5 and d2 are on the same diagonal. So are c6 and f3, and e7 and h4.

[quote]Bujo wrote:
I want to have safe sex with three women, any of whom may be carrying an STD (I like the classy dames). However, I only have two condoms :frowning:

How do I fuck each one while ensuring that no STD is passed from one woman to another or to myself for that matter?
[/quote]

Double dip…or, you could triple dip and save the second condom for another night

[quote]malonetd wrote:
Chewie wrote:
Bujo wrote:
Place 8 Queens on a chess board in a manner in which none can capture another.

a5, b1, c6, d2, e7, f3, g8, h4

That solution doesn’t work. (Unless I misunderstand your notation.)

a2, b4, c6, d8, e3, f1, g7, h5

Of course there are several other solutions.[/quote]

There is a handful of original combinations that will work, and once one set up is established then rotations and reflections can increase the number of solutions.

And you’re right. d2 won’t work with a5 using Chewie’s solution. I missed it doing it in my head, but once I put it on paper I caught it.

Imagine an analog clock set to 12 o’clock. Note that the hour and minute hands overlap. How many times each day do both the hour and minute hands overlap? How would you determine the exact times of the day that this occurs?

[quote]Bujo wrote:
Imagine an analog clock set to 12 o’clock. Note that the hour and minute hands overlap. How many times each day do both the hour and minute hands overlap? How would you determine the exact times of the day that this occurs?[/quote]

11 times.

[quote]malonetd wrote:
Chewie wrote:
Bujo wrote:
Place 8 Queens on a chess board in a manner in which none can capture another.

a5, b1, c6, d2, e7, f3, g8, h4

That solution doesn’t work. (Unless I misunderstand your notation.)

a2, b4, c6, d8, e3, f1, g7, h5

Of course there are several other solutions.[/quote]

woops. I wrote it down wrong.

a4, b1, c5, d2, e6, f3, g7, h4

[quote]malonetd wrote:
Bujo wrote:
Imagine an analog clock set to 12 o’clock. Note that the hour and minute hands overlap. How many times each day do both the hour and minute hands overlap? How would you determine the exact times of the day that this occurs?

11 times.[/quote]

You Sure?


You are looking at a corner of a single die.

Can you identify at least one of the sides visible through the hole?