[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
That’s inappropriate. Reporting to mods…
[quote]Voluminous wrote:
If g = log, (ax) then pz =
23g
Px
19
21a
25
Any ideas ?
[/quote]
Just blow in it like an old Nintendo cartridge…
the answer is pizza
[quote]DoubleDuce wrote:
At first I was disappointed there wasn’t a math question. But then mostly I was sad at myself because I realized I was disappointed there was no math question.[/quote]
haha same
Is there some kind of hidden joke here it something?
32oz. of quartz?
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
Dude I was just thinking of something witty to write and then you threw this real crap at me and derailed my train of thought. I hate you!
[quote]Dr.Matt581 wrote:
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[/quote]
wut
[quote]Dr.Matt581 wrote:
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[/quote]
Its not for a class, its part of a proof I am doing for my Phd. I know the formulas, and was going to post them as a handy hint later. But I have been so far frustrated by not being able to find a quotient rule for higher derivatives either in textbooks or in papers (despite the fact that you can easily derive it from these formulas), so temporarily decided to avoid this part of the proof.
[quote]Dr.Matt581 wrote:
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[/quote]
Damn-- Shit just got real!!!
Squats and milk.
tweet
[quote]lnname wrote:
[quote]Dr.Matt581 wrote:
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[/quote]
Its not for a class, its part of a proof I am doing for my Phd. I know the formulas, and was going to post them as a handy hint later. But I have been so far frustrated by not being able to find a quotient rule for higher derivatives either in textbooks or in papers (despite the fact that you can easily derive it from these formulas), so temporarily decided to avoid this part of the proof.[/quote]
now i know what to look forward to after college…
[quote]Dr.Matt581 wrote:
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[/quote]
[quote]lnname wrote:
[quote]Dr.Matt581 wrote:
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[/quote]
Its not for a class, its part of a proof I am doing for my Phd. I know the formulas, and was going to post them as a handy hint later. But I have been so far frustrated by not being able to find a quotient rule for higher derivatives either in textbooks or in papers (despite the fact that you can easily derive it from these formulas), so temporarily decided to avoid this part of the proof.[/quote]
If you think back to your calc one days, your professor probably told you that the quotient rule is never needed since it is just a special form of the product rule and chain rule and that every quotient can be expressed as a product by multiplying the numerator by the inverse of the denominator. This is why you won’t find a quotient rule for higher derivatives in any textbook, it is just not needed.
^slayed like a boss
[quote]Dr.Matt581 wrote:
[/quote]
Out of interest, what are you academic credentials? Apologies if you have mentioned them elsewhere.
[quote]yolo84 wrote:
[quote]Dr.Matt581 wrote:
[/quote]
Out of interest, what are you academic credentials? Apologies if you have mentioned them elsewhere.[/quote]
Well looking at his name I would go with PHD.
[quote]Derek542 wrote:
[quote]yolo84 wrote:
[quote]Dr.Matt581 wrote:
[/quote]
Out of interest, what are you academic credentials? Apologies if you have mentioned them elsewhere.[/quote]
Well looking at his name I would go with PHD. [/quote]
Thanks for your help!
I meant more along the lines of particular areas, what is he currently teaching etc.
[quote]Derek542 wrote:
[quote]Dr.Matt581 wrote:
[quote]lnname wrote:
for everyone that wanted a maths question, here is one.
given
y=f(g(x))/h(g(x))
where f and h are linear functions of g(x)
?
[/quote]
What class are you taking that you would be asked to do this? This is a very difficult problem to solve since it involves multiple compositions, but it is doable with a lot of time and effort. I am assuming that you have been given this problem for a class so I will not do a full proof for you, but I can give you a general idea on what you need to do. Plus, I do not want to work out a full proof. I did plenty of that in college. First, you must decide on how to begin. This starts out as a product rule problem,you should start by using the General Leibniz Rule, which is:
d[3] y/ dx[4] = [sigma k=0 to n] (binomial coefficient)(f^k)((h^-1)^n-k)
but you are going to have to take into account that both f and h are both compositions of the function g(x), which means that you are going to need to expand both f^k and (h^-1)^n-k using Faa di Bruno’s Formula. It is too tedious to type out Faa di Bruno’s Formula so you will have to look it up. It should be in your textbook or notes somewhere. Or just google it, it is a very commonly used formula so you will not have any trouble finding it. I hope this helps.
[/quote]
[/quote]
LMAO @ the gif!