[quote]theuofh wrote:
Found an error in my answer:
|x+j*y| = sqrt(x^2+y^2)
What are you studying Jasmincar?[/quote]
Oh I didnt read that before posting. Now it works. thanks
Now that I currently have no jobs and not at school I am trying to go as far as I can in Maths before starting school again. I got a bunch of books and 6 months.
[quote]Headhunter wrote:
[quote]theuofh wrote:
[quote]jasmincar wrote:
sigma*(x,y)=t*abs(x,y). They say this is real. I dont understand
[/quote]
I think what they are trying to get at here is |x+j*y| = (x+jy)(x-jy)
Therefore the magnitude of a complex number is equal to the product of it with its complex conjugate (x^2+j xy - j xy - j^2y^2) = (x^2+y^2) which is a real number.
Complex conjugates will be symmetric about the real axis (x). This is invariable to a scaling such that a*|x+jy| = a(x^2+y^2)
[/quote]
Yes. The product of a complex number with its conjugate is always real.
Good answer.
[/quote]
“Shit just got real”
Bahaha!!
[quote]jasmincar wrote:
sigma=tz= t*(complexconjugate(x,y)/I(x,y)I)
sigma*(x,y)=tI(x,y)I/I(x,y)I
sigma(x,y)=t
[/quote]
Weird. When I put this into the Google Translator it does nothing!!! Google is broked!
[quote]Stern wrote:
[quote]jasmincar wrote:
sigma=tz= t*(complexconjugate(x,y)/I(x,y)I)
sigma*(x,y)=tI(x,y)I/I(x,y)I
sigma(x,y)=t
[/quote]
Weird. When I put this into the Google Translator it does nothing!!! Google is broked!
[/quote]
Dude, you’re doing it wrong. You have to use Wolfram Alpha for that shit!
He’s the boss.
What if DOG actaully spelled CAT???